Health Insurance Coverage in Allen County, OH
ACS 2024 5-Year Estimates
94.1%
Rank #1,009/3,222 · #44 in OH
69th
Allen 94.1%
OH 93.6% +0.6%
US 91.7% +2.6%
Health Insurance Coverage Trend
Rankings →Percentile Rank Over Time
Year-over-Year Insurance Change
National Distribution
How Allen County's health insurance coverage of 94.1% compares to all 3,222 U.S. counties. Values range from 55.4% to 100.0%.
Distribution of Health Insurance Coverage Across All Counties
Ranking Context
Counties ranked closest to Allen County for health insurance coverage.
Nearby Rankings
Full ranking →| #1,006 | Cheboygan County, MI | 94.1% |
| #1,007 | Fairfield County, OH | 94.1% |
| #1,008 | Cottonwood County, MN | 94.1% |
| #1,009 | Allen County, OH | 94.1% |
| #1,010 | New Castle County, DE | 94.1% |
| #1,011 | Berkeley County, WV | 94.1% |
| #1,012 | Belknap County, NH | 94.1% |
About Health Insurance Coverage
Allen County, Ohio has a health insurance coverage of 94.1%, ranking #1,009 of 3,222 counties nationwide — 2.6% above the national value of 91.7%. Within Ohio, it ranks #44 of 88. This places it in the 69th percentile nationally.
Percentage of the population with health insurance coverage. Source: U.S. Census Bureau, American Community Survey 2024 5-Year Estimates. All values are estimates derived from survey samples and are subject to margin of error. For more information, see our methodology.