Health Insurance Coverage in Medina County, OH
ACS 2024 5-Year Estimates
96.0%
Rank #291/3,222 · #9 in OH
91th
Medina 96.0%
OH 93.6% +2.6%
US 91.7% +4.7%
Health Insurance Coverage Trend
Rankings →Percentile Rank Over Time
Year-over-Year Insurance Change
National Distribution
How Medina County's health insurance coverage of 96.0% compares to all 3,222 U.S. counties. Values range from 55.4% to 100.0%.
Distribution of Health Insurance Coverage Across All Counties
Ranking Context
Counties ranked closest to Medina County for health insurance coverage.
Nearby Rankings
Full ranking →| #288 | Columbia County, PA | 96.0% |
| #289 | Caledonia County, VT | 96.0% |
| #290 | Van Wert County, OH | 96.0% |
| #291 | Medina County, OH | 96.0% |
| #292 | Kendall County, IL | 96.0% |
| #293 | Robertson County, KY | 96.0% |
| #294 | Douglas County, MN | 96.0% |
About Health Insurance Coverage
Medina County, Ohio has a health insurance coverage of 96.0%, ranking #291 of 3,222 counties nationwide — 4.7% above the national value of 91.7%. Within Ohio, it ranks #9 of 88. This places it in the 91th percentile nationally.
Percentage of the population with health insurance coverage. Source: U.S. Census Bureau, American Community Survey 2024 5-Year Estimates. All values are estimates derived from survey samples and are subject to margin of error. For more information, see our methodology.