Health Insurance Coverage in Sac County, IA
ACS 2024 5-Year Estimates
95.2%
Rank #541/3,222 · #47 in IA
83th
Sac 95.2%
IA 95.0% +0.2%
US 91.7% +3.8%
Health Insurance Coverage Trend
Rankings →Percentile Rank Over Time
Year-over-Year Insurance Change
National Distribution
How Sac County's health insurance coverage of 95.2% compares to all 3,222 U.S. counties. Values range from 55.4% to 100.0%.
Distribution of Health Insurance Coverage Across All Counties
Ranking Context
Counties ranked closest to Sac County for health insurance coverage.
Nearby Rankings
Full ranking →| #538 | Muhlenberg County, KY | 95.2% |
| #539 | Portage County, WI | 95.2% |
| #540 | Itasca County, MN | 95.2% |
| #541 | Sac County, IA | 95.2% |
| #542 | Manistee County, MI | 95.2% |
| #543 | East Feliciana Parish, LA | 95.2% |
| #544 | Dearborn County, IN | 95.2% |
About Health Insurance Coverage
Sac County, Iowa has a health insurance coverage of 95.2%, ranking #541 of 3,222 counties nationwide — 3.8% above the national value of 91.7%. Within Iowa, it ranks #47 of 99. This places it in the 83th percentile nationally.
Percentage of the population with health insurance coverage. Source: U.S. Census Bureau, American Community Survey 2024 5-Year Estimates. All values are estimates derived from survey samples and are subject to margin of error. For more information, see our methodology.