Health Insurance Coverage in Sandusky County, OH
ACS 2024 5-Year Estimates
Health Insurance Coverage Trend
Rankings →Percentile Rank Over Time
Year-over-Year Insurance Change
National Distribution
How Sandusky County's health insurance coverage of 93.7% compares to all 3,222 U.S. counties. Values range from 55.4% to 100.0%.
Distribution of Health Insurance Coverage Across All Counties
Ranking Context
Counties ranked closest to Sandusky County for health insurance coverage.
Nearby Rankings
Full ranking →| #1,142 | San Joaquin County, CA | 93.7% |
| #1,143 | Emmons County, ND | 93.7% |
| #1,144 | Sheridan County, ND | 93.7% |
| #1,145 | Sandusky County, OH | 93.7% |
| #1,146 | Henry County, VA | 93.7% |
| #1,147 | Codington County, SD | 93.7% |
| #1,148 | Pickett County, TN | 93.7% |
About Health Insurance Coverage
Sandusky County, Ohio has a health insurance coverage of 93.7%, ranking #1,145 of 3,222 counties nationwide — 2.2% above the national value of 91.7%. Within Ohio, it ranks #50 of 88. This places it in the 64th percentile nationally.
Percentage of the population with health insurance coverage. Source: U.S. Census Bureau, American Community Survey 2024 5-Year Estimates. All values are estimates derived from survey samples and are subject to margin of error. For more information, see our methodology.