Health Insurance Coverage in Sheboygan County, WI
ACS 2024 5-Year Estimates
Health Insurance Coverage Trend
Rankings →Percentile Rank Over Time
Year-over-Year Insurance Change
National Distribution
How Sheboygan County's health insurance coverage of 96.0% compares to all 3,222 U.S. counties. Values range from 55.4% to 100.0%.
Distribution of Health Insurance Coverage Across All Counties
Ranking Context
Counties ranked closest to Sheboygan County for health insurance coverage.
Nearby Rankings
Full ranking →| #292 | Kendall County, IL | 96.0% |
| #293 | Robertson County, KY | 96.0% |
| #294 | Douglas County, MN | 96.0% |
| #295 | Sheboygan County, WI | 96.0% |
| #296 | Lyon County, IA | 96.0% |
| #297 | East Carroll Parish, LA | 96.0% |
| #298 | Nelson County, ND | 96.0% |
About Health Insurance Coverage
Sheboygan County, Wisconsin has a health insurance coverage of 96.0%, ranking #295 of 3,222 counties nationwide — 4.7% above the national value of 91.7%. Within Wisconsin, it ranks #13 of 72. This places it in the 91th percentile nationally.
Percentage of the population with health insurance coverage. Source: U.S. Census Bureau, American Community Survey 2024 5-Year Estimates. All values are estimates derived from survey samples and are subject to margin of error. For more information, see our methodology.