Health Insurance Coverage in Floyd County, IA
ACS 2024 5-Year Estimates
96.4%
Rank #180/3,222 · #22 in IA
94th
Floyd 96.4%
IA 95.0% +1.5%
US 91.7% +5.1%
Health Insurance Coverage Trend
Rankings →Percentile Rank Over Time
Year-over-Year Insurance Change
National Distribution
How Floyd County's health insurance coverage of 96.4% compares to all 3,222 U.S. counties. Values range from 55.4% to 100.0%.
Distribution of Health Insurance Coverage Across All Counties
Ranking Context
Counties ranked closest to Floyd County for health insurance coverage.
Nearby Rankings
Full ranking →| #177 | Bond County, IL | 96.4% |
| #178 | Sangamon County, IL | 96.4% |
| #179 | Mercer County, OH | 96.4% |
| #180 | Floyd County, IA | 96.4% |
| #181 | Dane County, WI | 96.4% |
| #182 | Huerfano County, CO | 96.4% |
| #183 | Cecil County, MD | 96.4% |
About Health Insurance Coverage
Floyd County, Iowa has a health insurance coverage of 96.4%, ranking #180 of 3,222 counties nationwide — 5.1% above the national value of 91.7%. Within Iowa, it ranks #22 of 99. This places it in the 94th percentile nationally.
Percentage of the population with health insurance coverage. Source: U.S. Census Bureau, American Community Survey 2024 5-Year Estimates. All values are estimates derived from survey samples and are subject to margin of error. For more information, see our methodology.