Health Insurance Coverage in Milwaukee County, WI
ACS 2024 5-Year Estimates
Health Insurance Coverage Trend
Rankings →Percentile Rank Over Time
Year-over-Year Insurance Change
National Distribution
How Milwaukee County's health insurance coverage of 92.8% compares to all 3,222 U.S. counties. Values range from 55.4% to 100.0%.
Distribution of Health Insurance Coverage Across All Counties
Ranking Context
Counties ranked closest to Milwaukee County for health insurance coverage.
Nearby Rankings
Full ranking →| #1,443 | Logan County, CO | 92.8% |
| #1,444 | Cleburne County, AR | 92.8% |
| #1,445 | Allen Parish, LA | 92.8% |
| #1,446 | Milwaukee County, WI | 92.8% |
| #1,447 | Yancey County, NC | 92.8% |
| #1,448 | Perry County, AL | 92.8% |
| #1,449 | Randolph County, AR | 92.8% |
About Health Insurance Coverage
Milwaukee County, Wisconsin has a health insurance coverage of 92.8%, ranking #1,446 of 3,222 counties nationwide — 1.2% above the national value of 91.7%. Within Wisconsin, it ranks #60 of 72. This places it in the 55th percentile nationally.
Percentage of the population with health insurance coverage. Source: U.S. Census Bureau, American Community Survey 2024 5-Year Estimates. All values are estimates derived from survey samples and are subject to margin of error. For more information, see our methodology.