Health Insurance Coverage in Osceola County, FL
ACS 2024 5-Year Estimates
Health Insurance Coverage Trend
Rankings →Percentile Rank Over Time
Year-over-Year Insurance Change
National Distribution
How Osceola County's health insurance coverage of 89.4% compares to all 3,222 U.S. counties. Values range from 55.4% to 100.0%.
Distribution of Health Insurance Coverage Across All Counties
Ranking Context
Counties ranked closest to Osceola County for health insurance coverage.
Nearby Rankings
Full ranking →| #2,293 | Fremont County, ID | 89.4% |
| #2,294 | Monroe County, MO | 89.4% |
| #2,295 | Coryell County, TX | 89.4% |
| #2,296 | Osceola County, FL | 89.4% |
| #2,297 | Walworth County, SD | 89.4% |
| #2,298 | Rockingham County, VA | 89.4% |
| #2,299 | Morton County, KS | 89.4% |
About Health Insurance Coverage
Osceola County, Florida has a health insurance coverage of 89.4%, ranking #2,296 of 3,222 counties nationwide — 2.5% below the national value of 91.7%. Within Florida, it ranks #27 of 67. This places it in the 29th percentile nationally.
Percentage of the population with health insurance coverage. Source: U.S. Census Bureau, American Community Survey 2024 5-Year Estimates. All values are estimates derived from survey samples and are subject to margin of error. For more information, see our methodology.