Health Insurance Coverage in Seneca County, OH
ACS 2024 5-Year Estimates
94.7%
Rank #761/3,222 · #27 in OH
76th
Seneca 94.7%
OH 93.6% +1.2%
US 91.7% +3.3%
Health Insurance Coverage Trend
Rankings →Percentile Rank Over Time
Year-over-Year Insurance Change
National Distribution
How Seneca County's health insurance coverage of 94.7% compares to all 3,222 U.S. counties. Values range from 55.4% to 100.0%.
Distribution of Health Insurance Coverage Across All Counties
Ranking Context
Counties ranked closest to Seneca County for health insurance coverage.
Nearby Rankings
Full ranking →| #758 | Monmouth County, NJ | 94.7% |
| #759 | Polk County, IA | 94.7% |
| #760 | Bayfield County, WI | 94.7% |
| #761 | Seneca County, OH | 94.7% |
| #762 | Cumberland County, IL | 94.7% |
| #763 | Kane County, UT | 94.7% |
| #764 | McCone County, MT | 94.7% |
About Health Insurance Coverage
Seneca County, Ohio has a health insurance coverage of 94.7%, ranking #761 of 3,222 counties nationwide — 3.3% above the national value of 91.7%. Within Ohio, it ranks #27 of 88. This places it in the 76th percentile nationally.
Percentage of the population with health insurance coverage. Source: U.S. Census Bureau, American Community Survey 2024 5-Year Estimates. All values are estimates derived from survey samples and are subject to margin of error. For more information, see our methodology.