Health Insurance Coverage in Dane County, WI
ACS 2024 5-Year Estimates
Health Insurance Coverage Trend
Rankings →Percentile Rank Over Time
Year-over-Year Insurance Change
National Distribution
How Dane County's health insurance coverage of 96.4% compares to all 3,222 U.S. counties. Values range from 55.4% to 100.0%.
Distribution of Health Insurance Coverage Across All Counties
Ranking Context
Counties ranked closest to Dane County for health insurance coverage.
Nearby Rankings
Full ranking →| #178 | Sangamon County, IL | 96.4% |
| #179 | Mercer County, OH | 96.4% |
| #180 | Floyd County, IA | 96.4% |
| #181 | Dane County, WI | 96.4% |
| #182 | Huerfano County, CO | 96.4% |
| #183 | Cecil County, MD | 96.4% |
| #184 | Olmsted County, MN | 96.4% |
About Health Insurance Coverage
Dane County, Wisconsin has a health insurance coverage of 96.4%, ranking #181 of 3,222 counties nationwide — 5.1% above the national value of 91.7%. Within Wisconsin, it ranks #9 of 72. This places it in the 94th percentile nationally.
Percentage of the population with health insurance coverage. Source: U.S. Census Bureau, American Community Survey 2024 5-Year Estimates. All values are estimates derived from survey samples and are subject to margin of error. For more information, see our methodology.